find the width of the rectangle.
2007-04-26 06:37:38 · 4 answers · asked by starlight l 2 in Education & Reference ➔ Homework Help
P = 2L + 2W
30 = 2(6+2W) +2W
distribute
30 = 12 + 4W + 2W
combine all like terms (subtract 12 from both sides and add 4W and 2W)
18 = 6W
divide by 6 on both sides
W = 3
2007-04-26 06:45:21 · answer #1 · answered by dewkisses02 4 · 0⤊ 0⤋
L = 2W +6
30 = 2W + 2L
Subsitute first into second equation
30 = 2W + 2 (2W+ 6)
30 = 6W + 12
W = 3
L = 2(3) + 6 = 12
2007-04-26 13:47:55 · answer #2 · answered by ignoramus 7 · 0⤊ 0⤋
L = length
W = width
L=6+2w
perimeter = L + L + W + W
30 = (6 + 2w) + (6 +2w) + w + w
30 = 6w + 12
18 = 6w
3 = w
2007-04-26 13:43:45 · answer #3 · answered by math guru 4 · 0⤊ 1⤋
l=6+2w
w
2(6+2w)+2w=30
12+4w+2w=30
12+6w=30
6w+18
w=3
l=12
2007-04-26 13:43:49 · answer #4 · answered by ashleyk 2 · 0⤊ 0⤋