Since this compound doesn't have any double bonds, and because it isn't a cyclic compound, it cannot have cis/trans isomers.
2007-04-26 06:38:38
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answer #1
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answered by hcbiochem 7
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With a unmarried double bond in a molecule, you only get a pair of E/Z isomers even as both side of the double bond have 2 diverse communities connected. that is not a probability for both communities connected to at least one side of double bond to regulate places - double bonds do not enable rotation. for instance: XYC=CXX isn't E/Z because there are 2 X communities connected to at least one side - and for this reason it would not be counted which way round they bypass, the molecule nonetheless seems the same. (the position X,Y,A are any communities connected to the double bond.) yet: XYC=CXA is E/Z because both both communities X and Y, and both communities X and A on the different side are diverse from one yet another. The molecule with both X on the proper isn't like the molecule with one X on the proper and one X on the bottom. no be counted the way you bypass it, you won't be able to get it to seem the same (it really is non-superimposable). So: 2,3 dibromo-a million-hexene has communities on one side of double bond: H and H, and on the different side: Br and C4H8Br. As one side has similar communities (H and H), this molecule won't be able to be E/Z. So: a million,2 dibromo-a million-hexene has communities on one side of double bond: H and Br, and on the different side:Br and C4H9. As both side have pairs of diverse communities, this molecule has 2 isomers E/Z. as an celebration: Is BrHC=CHBr E/Z or not? As both side of the double bond have pairs of diverse communities (Br & H, and Br & H), the answer is bound. There are 2 isomers of one million,2-dibromoethene: E-a million,2-dibromoethene and Z-a million,2-dibromoethene. Is Br2C=CH2 E/Z or not? As a minimum of one side of double bond (in reality both side) have a pair of similar communities (H & H, and Br & Br), the answer is not any. there is just one type of one million,a million-dibromoethene. wish this permits clarify issues!
2016-12-04 22:03:21
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answer #2
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answered by Anonymous
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