1.x^2+8x= -16
2.3x^2=2x+5
2007-04-26 06:19:40 · 5 answers · asked by gloriousnina 2 in Education & Reference ➔ Homework Help
x^2 + 8x + 16 = 0
(x + 4) (x + 4) = 0
x = -4
3x^2 = 2x + 5
3x^2- 2x -5 = 0
(3x-5)(x+1) = 0
3x -5 = 0 ... x = 5/3
x + 1 = 0... x = -1
x = 5/3 and x = -1
2007-04-26 06:26:19 · answer #1 · answered by blueskies 7 · 0⤊ 0⤋
1. x^2+8x+16=0
(x+4)(x+4)=0
x=-4
2.3x^2-2x-5=0
(3x-5)(x+1)
x= 5/3 or -1
plug numbers into equation to see if the solution works.
2007-04-26 13:31:08 · answer #2 · answered by bobbyjay 3 · 0⤊ 0⤋
Add the 16 on the 1st problem on the other side of the equation. get 0 on the right side. factor as (x+4)(x+4)=0, so therefore, x= -4. factor the second one as (3x-5)(x+1)=0, therefore x=5/3 and x= -1
2007-04-26 13:29:00 · answer #3 · answered by Juan 1 · 0⤊ 0⤋
x^2+8x+16=0
(x+4)(x+4)=0
x=-4
3x^2-2x-5=0
(3x-5)(x+1)=0
x=5/3 or -1
2007-04-26 15:46:04 · answer #4 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
that is easy.ask ur math teacher
2007-04-26 13:27:49 · answer #5 · answered by Giri d 1 · 0⤊ 0⤋