factor and find all roots x^3-3x^2-4x+12=0?

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factor and find all roots x^3-3x^2-4x+12=0?

2007-04-26 05:30:06 · 3 answers · asked by Enrique g 1 in Science & Mathematics ➔ Mathematics

3 answers

Factor it as (x-3)(x^2 -4)=(x-3)(x-2)(x+2).

The roots are 3,2, and -2.

2007-04-26 05:35:51 · answer #1 · answered by mathematician 7 · 0⤊ 0⤋

x^3-3x^2-4x+12=0

Factor x^2 out of first two terms
and -4 out of next two terms.

x^2(x-3) - 4(x-3) = 0

Now factor out x-3

(x-3)(x^2-4) = 0

or

(x-3)(x+2)(x-2) = 0

so the roots are x=3, x=2, x=-2

2007-04-26 12:44:58 · answer #2 · answered by Robert L 7 · 0⤊ 0⤋

(x-3)(x-2)(x+2)=0 x=3,2,-2 as roots.

2007-04-26 12:35:38 · answer #3 · answered by bruinfan 7 · 0⤊ 0⤋