Given that E°=0.52V for the reduction Cu+(aq) + e- ---> Cu(s), calculate E° for the following reaction at 25°C.
2Cu+(aq) --->Cu2+(aq) + Cu(s)
If anyone can show me how to do this problem, I would greatly appreciate it. It's not a homework problem or anything that is to be turned in, it's just something I cannot remember how to do. Thanks.
2007-04-26 04:05:06 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
This is, of course, a disproportionation reaction, and you have only quoted one of the two electrode potentials necessary.
Cu+ + e- -----> Cu (+0.52V)
Cu2+ + e- ----> Cu+ is what you needed to look up (it's +0.15V)
The the Eo for the disproportionation reaction is the difference between the two, and in this case it is positive, leading to a negative delta G value.
2007-04-29 05:58:53 · answer #1 · answered by Gervald F 7 · 0⤊ 0⤋