44x^2+16x-3=0
2007-04-26 03:26:33 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
You could factor the polynomial, but that tends to be difficult when the coefficient of x^2 is large. For this problem, I recommend the quadratic formula. If you express the quadratic polynomial as ax^2 + bx + c = 0, then x = [-b +/- sqrt(b^2 - 4ac)] / 2a.
x =
[-16 +/- sqrt(16^2 - 4*44*(-3))] / (2*44) =
[-16 +/- sqrt(784)] / 88 =
(-16 +/- 28) / 88 =
( -44 or 12) / 88 =
-1/2 or 3/22 =
-0.5 or 0.136
2007-04-26 03:29:33 · answer #1 · answered by DavidK93 7 · 0⤊ 0⤋
(22x - 3)(2x + 1) = 0
Equation equals 0 at:
22x - 3 = 0 or x = 3/22, and
2x + 1 = 0 or x = -1/2
2007-04-26 10:31:59 · answer #2 · answered by Brad K 3 · 0⤊ 0⤋
(22x-3)(2x+1) = 0
x = 3/22, -1/2
2007-04-26 10:32:59 · answer #3 · answered by kellenraid 6 · 0⤊ 0⤋