Solve the equation.?

0 ⤊

x(4x-3)=7

use a comma to seperate answers as needed.

2007-04-26 02:51:51 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

x(4x - 3) = 7

4x^2 - 3x = 7

4x^2 - 3x - 7 = 0

(4x - 7)(x + 1) = 0

x = 7/4
x = -1

2007-04-26 02:56:36 · answer #1 · answered by Anonymous · 0⤊ 0⤋

4x^2 - 3x - 7 = 0
(x+1)(4x-7)=0
x = -1 or x = 7/4

2007-04-26 09:56:42 · answer #2 · answered by N.y.Rych 1 · 0⤊ 0⤋

4x^2 - 3x - 7 = 0
(4x-7)(x+1) = 0

x = 7/4 , -1

2007-04-26 10:00:37 · answer #3 · answered by Robert L 7 · 0⤊ 0⤋

4x^2 - 3x - 7 = 0
4x^2 + 4x - 7x - 7 = 0
4x(x+1) - 7(x+1) = 0
(x+1)(4x-7)=0

x = -1
x = 7/4

2007-04-26 09:57:36 · answer #4 · answered by gudspeling 7 · 0⤊ 0⤋