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You need to examine each individual character of the string to check if it is a letter or character. Will you allow spaces?

See the link below for details of how to use the methods
isDigit(char ch)
isLetter(char ch)
isLetterOrDigit(char ch)
isSpaceChar(char ch)

2007-04-26 02:56:33 · answer #1 · answered by AnalProgrammer 7 · 0 0

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