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1: Find the GCF:
-33x2 - 231x

-33x -33 -3x


2: 9x3 - 10x2 - 12x
x 3 3x


3: Factor out the GCF:
-18x2 + 4x

x(9x - 2)
-2(9x - 2)
-2x(9x - 2)


4: -3x2 + 15x
-x(x - 5)
-3x(x - 5)
x(x - 5)


5: -2x2 - 18x
x(x + 9)
-2x(x - 9)
-2x(x + 9)


6: 36x3 + 24x2 + 20x
2x(9x2 + 6x + 5)
4x(9x2 + 6x + 5)
4(9x2 + 6x + 5)


7: Factor by grouping:
2x2 + 4x + 3x + 6

(2x + 3) (x + 2)
(x + 3) (x + 2)
(x2 + 3) (x + 2)


8: 2x2 - 4x + x - 2
Hint: When there is no apparent coefficient, the coefficient is actually one.

(x + 1) (x - 2)
(2x + 1) (x - 2)
(x + 1) (x + 2)


9: 6x2 + 9x + 4x + 6
(3x + 2) (x + 3)
(x + 2) (2x + 3)
(3x + 2) (2x + 3)


10: x3 + 2x + 3x2 + 6
(x2 + 3) (x + 2)
(x + 3) (x + 2)
(x + 3) (x2 + 2)


11: x3 - 4x2 + 2x - 8
(x2 + 2) (x - 4)
(x+ 2) (x2 - 4)
(x + 2) (x - 4)


12: 3x3 + 4x2 - 6x - 8
(x2 - 2) ( x + 4)
(x2 - 2) ( 3x + 4)
(x - 2) ( 3x + 4)


13: 4x2 + 8x + 6x + 12
2(x + 3) (x + 2)
2(2x + 3) (x + 2)
2(x2 + 3) (x + 2)


14: 3x3 + 6x2 + 9x + 18
3(x + 3) (x + 2)
3(2x + 3) (x + 2)
3(x2 + 3) (x + 2)


15: Factor the difference of two squares:
x2 - 9

(x + 3)(x -3)
(3 - x)(x - 3)
(x - 3)(x -3)


16: y2 - 16
(y + 4)(y + 4)
(y + 4)(4 - y)
(y + 4)(y - 4)


17: w2 - 4
(w + 2)( 2 - w)
(w + 2)( w - 2)
(w - 2)( w -2)


18: Factor using any technique:
75 - 3z2

3(5 + z)(5 - z)
8(z + 5)(z - 5)
(5 + z)(5 - z)


19: a2b + 3a2 - 4b - 12
(a - 2)(a + 2)(b + 3)
(a2 - 2)(a + 2)(b + 3)
(a - 2)(a - 2)(b + 3)


20: a2 + 4
(a + 1)(a + 1)
(a + 2)(a - 2)
This can't be factored

2007-04-25 22:03:28 · 5 answers · asked by laney s 1 in Science & Mathematics Mathematics

5 answers

- 3x² - 231

- 3x(11x + 77

- - - - - - - - - -

- 33x - 33 - 3x

- 3(11x - 11 - x)

- - - - - - - - -

- 18x² + 4x

- 2x(9x - 2)

- - - - - - - --

- 3x² + 15x

- 3x(x - 5)

- - - - - - -- - -

- 2x² - 18x

- 2x(x + 9)

- - - - - - - - - -

36x³ + 24x² + 20x

4x(9x + 6x + 5)

- - - - - - - - -- - - - -s-

2007-04-25 22:37:22 · answer #1 · answered by SAMUEL D 7 · 4 0

-33x² - 231x =
GCF(33 and 231) = 33
><
-33x -33 -3x
GCF(33 and 3) = 3
-36x - 33 = 3(-12x -11)
<>
2: 9x³ - 10x² - 12x = GCF(9x³, 10x² and 12x) = x
<>
3: Factor out the GCF:
-18x² + 4x =
GCF(-18x² and 4x) = 2x
2x(-9x + 2)
><
4: -3x² + 15x =
GCF(-3x² and 15x) = 3x
3x(-x + 5)
><
5: -2x² - 18x
GCF(-2x² and 18x) = 2x
2x(-x -9)
><
6: 36x³ + 24x² + 20x =
GCF(36x³, 24x² and 20x) = 4x
4x(9x² + 6x + 5) = 0
<>
7: Factor by grouping:
2x² + 4x + 3x + 6
2x(x + 2) + 3(x + 2) =
(x + 2)(2x + 3)
><
8: 2x² - 4x + x - 2
2x(x - 2) + 1(x - 2) =
(2x + 1)(x - 1)
><
9: 6x² + 9x + 4x + 6 =
3x(2x + 3) + 2(2x + 3) =
(3x + 2)(x + 3)
><
10: x³ + 2x + 3x² + 6 =
x(x² + 2) + 3(x² + 2) =
(x + 3) (x² + 2)
><
11: x³ - 4x + 2x - 8 =
x(x² - 4) + 2(x - 4) =
(x + 2)(x - 2) (x - 4)
><
12: 3x³ + 4x² - 6x - 8
x²(3x - 4) - 2(3x - 4) =
(x² - 2)(3x - 4)
><
13: 4x² + 8x + 6x + 12
4x(x + 2) + 6(x + 2)=
(4x + 6)(x + 2)
><
14: 3x³ + 6x² + 9x + 18
3x²(x + 2) + 9(x + 2) =
(3x² + 9)(x + 2) =
3(x² + 3)(x + 2)
><
15: Factor the difference of two squares:
x² - 9 = (x - 3)(x + 3)
><
16: y² - 16 = (y + 4)(y - 4)
><
17: w2 - 4 = (w + 2)( w - 2)
><
18: Factor using any technique:
75 - 3z² =
3(25 - z²) = 3(5 - z)(5 + z)
><
19: a²b + 3a² - 4b - 12 =
a²(b + 3) - 4(b + 3) =
(a-2)(a + 2)(b + 3)
><
20: a² + 4
This can't be factored
:::

2007-04-27 12:26:26 · answer #2 · answered by aeiou 7 · 1 0

the answer to volume 3 is: there'll be 39 scholars in 3 communities. There are 117 scholars all mutually (won't be able to be divided gently into 2 communities yet might want to be divided into 3 communities)

2016-12-04 21:38:47 · answer #3 · answered by ? 4 · 0 0

You will never learn if you always post this much. One example is enough, since the rules in solving them is the same. You will never learn solving math problems if you just copy the answer from us. You must understand WHY instead of HOW to do it. In the end, we are NOT beside YOU when you are taking an exam...good luck!!!

2007-04-26 00:29:28 · answer #4 · answered by detektibgapo 5 · 1 0

1. 33x
2. x
3. -2x(9x-2)
4. -3x(x-5)
5. -2x(x+9)
6. 4x(9x2+6x+5)
7. (2x+3)(x+2)
8.(2x+1)(x-2)
9.c
10.c
11.a
12.b
13.c
14.c
15.a
16.c
17.b
18.a
19.a
20.-

2007-04-25 22:36:39 · answer #5 · answered by solver 3 · 1 0

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