Need help with Math Problem! Can anyone tell me how to find the equation of (6,-3) slope of -7/9?

Question

Can anyone tell me how to find the equation of (6,-3) slope of -7/9? -- I know the answer but I can't figure out how to get there! A detailed example would be SO helpful thank you!!! This should be in slope-intercept form which is y=mx+b

Answer 1

Point - slope Equation:

y-y1 = m (x - x1)


Plug in the slope for m, and either of the given points for ( x1, y1 ). So here we are finding the equation of a line with slope -7/9 passing through the point (6.-3).

y-(-3) = -7/9(x-6)

Then convert to standard form:

Eliminate denominator

9(y+3) = 9 ( (-7/9)(x-6))

9y + 27 = -7x +42



Rearrange terms 7x + 9y = 15

In slope-intercept form:

y = -7/9x + 5/3

Answer 2

y = mx + b

m = slope = -7/9

y=-3, x=6

-3 = (-7/9)*6 + b

b = -5/3

y = (-7/9)x + 5/3

Answer 3

(h,k) ---> (6,3)

m (slope) ---> -7/9

Start out by using the point-slope formula: y - k = m(x - h)

Plug in the numbers: y - (-3) = -7/9(x -6)

y + 3 = -7/9(x - 6)

y + 3 = -7/9x + 14/3

Solution: y = -7/9x + 5/3

Answer 4

y = (-7/9)x + b.
-3 = (-7/9)6 + b
-27 = -42 +9b
9b=15
b = 5/3
y = (-7/9)x + 5/3
9y = -7x + 15
7x + 9y = 15

Answer 5

y + 3 = - (7/9)(x - 6)
9y + 27 = -7x + 42
7x + 9y = 15
y = - (7/9)x + 5/3

Answer 6

if you consider A(xa,ya) => (x-xa)*m=y-ya;
(x-6)*m=y+3;
-7x/9 + 14/3 = y+3;
-7x + 42=9y+27
-7x-9y+15=0
7x+9y-15=0;
9y=-7x+15;
y=-7/9x + 5/3;