Simplify (a-b+c)square???

Answer 1

(a-b+c)^2
=(a-b+c)(a-b+c)
=(a)(a) + (a)(-b) + (a)(c) + (-b)(-b) + (-b)(c) + (c)(c)
= a^2 -ab + ac + b^2 -bc + c^2

Answer 2

This is sort of like foiling, only a little bit more complicated. The easiest way to do this is set up the two side by side like so:

(a + b + c) (a + b + c)

Then from here, draw a line over top from the first a to every other term in the second one. a to a means a * a which is a^2. a to b means a * b which is just ab. Similarly, ac is the last one. Next, do the same thing with the first b. b to a means b * a which is ba or ab as well. Continue until you've come up with a total of 9 terms.

Now comes the simplifying part. see if a^2 has anything that looks like it - it doesn't, so you have just a^2 as part of the simplified answer. Next, look at ab, does it have anything like it? It will: there are 2 abs, which mean 2ab will be part of the answer. Continue on simplifying, and when you're done, you should have 6 terms, 3 are something squared, and 3 are 2 times something times something(like the 2ab)

Answer 3

( a-b+c)= (a+(-b)+c) sqaure

now substituting in the formula (a+b+c)square = a square+ b square + c square + 2 ab +2bc +2ca
= a square + (-b)square + c square + 2a(-b) + 2(-b)c+ 2ca=

a square + b square+ c square -2ab -2bc +2ca is d answer

Answer 4

(a - b + c)^2 =
a^2 - 2ab + b^2 - 2bc + c^2 + 2ac
...not sure which is simpler...