a certain row boat has the shape of a box: a rectangular bottom and rectangular sides. Its bottom is 1 meter wide and 3 meters long. the sides are 40 cm high. the empty mass of the boat is 50 kg. four men, 100 kg each go for a ride in the boat across a fresh water lake. With all the men in the boat, how many cm of the sides of the boat will remain above the water? convert kg to grams.
2007-04-25 19:49:56 · 1 answers · asked by trust2400 3 in Science & Mathematics ➔ Physics
To find the answer, you need to utilize the fact that a floating object displaces a volume of water that has mass equal to that of the floating object.
The total mass of all the objects is 50+100*4 = 450 kg. The density of water is 1000 kg per m^3. Therefore, the volume of water displaced is 0.45 m^3. Now you just need to solve for the height submerged:
length*width*height = 0.45 m^3
rearranging:
height = 0.45 m^3 / (length*width)
height = 0.45 m^3 / (1 m * 3 m)
height = 0.15 m
15 cm are below the water, so 40 - 15 = 25 cm remain above the water.
2007-04-25 22:00:36 · answer #1 · answered by lithiumdeuteride 7 · 0⤊ 0⤋