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I need to find the pH of 50 ml of 0.50 M K2HPO4-.

Ka1 for H3PO4 is 7.11x10^-3.
Ka2= 6.34 x 10^-8
Ka3= 4.30x10^-13.


Thanks!

2007-04-25 18:57:35 · 1 answers · asked by Mr Dawg 1 in Science & Mathematics Chemistry

1 answers

pKa1+pKa2 + log[Salt]/[Acid]

2007-04-25 20:50:50 · answer #1 · answered by ag_iitkgp 7 · 0 0

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