What are the odds that another Gauss would be born ?
2007-04-25 17:46:58 · 8 answers · asked by sandwreckoner 4 in Science & Mathematics ➔ Mathematics
I never got asked this question in math classes throughout my school life. But, I'd do it like this; ( 10 + 1 + 9 + 2 + 8 + 3 + 7 + 4 + 6 + 5 ) 10 = 5050.
2007-04-25 19:09:44 · update #1
yes they should
2007-04-25 17:53:21 · answer #1 · answered by iknowu2jan 3 · 1⤊ 0⤋
Well geez, you just rewrite the equation like this:
100 + 1 + 99 + 2 + 98 + 3 + ... + 51 + 50
There are 50 sets that add up to 101, so 50 * 101 = 5050.
And there's your answer. See if your class comes up with that.
2007-04-25 17:56:21 · answer #2 · answered by Anonymous · 1⤊ 0⤋
Gauss had already been born when he was presented with the problem. Although that problem is going to be drudgery, it will help students see patterns, and laziness is a great motivator for discovery. It does make a good punishment assignment, but under ordinary circumstances, I think it's a bad idea.
2007-04-25 17:55:11 · answer #3 · answered by novangelis 7 · 1⤊ 0⤋
It could prove to be a most instructive exercise. Odds against another Gauss "being born" are millions to one.
2007-04-25 17:59:29 · answer #4 · answered by Helmut 7 · 0⤊ 0⤋
yes becasue it would be a good way to introduce the easier way to add the terms in a arithmetic sequence.
2007-04-25 17:54:17 · answer #5 · answered by Rocketman 6 · 1⤊ 0⤋
Drill helps to establish memory. Boring, but true. We need some tedgium on our life and we need some imaginative time. a little of everything.
2007-04-25 17:56:15 · answer #6 · answered by jekin 5 · 0⤊ 1⤋
yes
2007-04-25 17:58:37 · answer #7 · answered by Anonymous · 0⤊ 0⤋
Why not? Thinking never hurt anyone!!
2007-04-25 17:55:34 · answer #8 · answered by Anonymous · 1⤊ 0⤋