Find the vector that has magnitude 3 and the same direction as 5i-12j.
If you can, please show steps. Thank you!
2007-04-25 17:35:34 · 3 answers · asked by S. Corleone 2 in Science & Mathematics ➔ Mathematics
The vector 5i-12 has magnitude sqrt(25+144)=13; so multiply this vector by (3/13) and it will have a magnitude of 3 and still go in the same direction: -36/13+15/36.
2007-04-25 17:40:10 · answer #1 · answered by bruinfan 7 · 0⤊ 0⤋
Do you mean 4i - 12j or 5i - 12j? I assume it's the latter.
The magnitude of the vector 5i - 12j is:
|| 5i - 12j || = √[5² + (-12)²] =√(25 + 144) = √169 = 13
To find a vector v, in the same direction with magnitude 3 multiply by 3/13.
v = (5i - 12j) * (3/13) = (15/13)i - (36/13)j
2007-04-26 10:23:51 · answer #2 · answered by Northstar 7 · 0⤊ 0⤋
first find the magnitude of the vector which is 7 now to have a vector with the same direction you must multiply by positive to have a vector with magnitude 21 we multiply by a number that makes the original magnitude to 21 we get +3 so we multiply each coordinates by 3 we get ( 6 , -18, 9)
2016-04-01 07:47:47 · answer #3 · answered by ? 4 · 0⤊ 0⤋