A 50 foot garden hose measures 1" outside diameter when it?

Question

is filled under pressure and the valve on the end is closed. When the fauscet is turned off and far valve opened water comes spraying out. After the water finishes spraying so the hose is full of water at air pressure, the outside diameter is 7/8" inch.
1. If the hose has 1/16" thick walls, how much water comes out? How much water remains in the hose?
2. If the hose has 1/8" thick walls, how much water comes out? How much water remains in the hose?

Answer 1

Part 1.
inner diameter of hose in relaxed state = 3/4 "
inner diameter of hose under pressure = sqrt(51)/8 "

From this, displaced water = 1125pi/32 cu. in.
= 1125pi/(32*231) gal. == 0.47812388... gal.

Volume of 600 in. hose in relaxed state = amount of water that remains in hose = 75*9pi/8 = 675pi/8 cu. in. = 675pi / (8*231) gal. == 1.14749732... gal
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Part 2.
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inner diameter of hose in relaxed state = 5/8 "
inner diameter of hose under pressure = sqrt(5/8) "

From this, displaced water = 1125pi/32 cu. in.
= 1125pi/(32*231) gal. == 0.47812388... gal. (same as in part 1)

Volume of 600 in. hose in relaxed state = amount of water that remains in hose = 75*25pi/32 = 1875pi/32 cu. in. = 1875pi / (32*231) gal. == 0.79687314... gal