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The half-life of iodine-131 is 8.10 days, so give your answer in days.

2007-04-25 15:33:50 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

0.48 = 0.5^(t/8.1)
t/8.1 = log(0.48)/log(0.5)
t = 8.1log(0.48)/log(0.5)
t = 8.577 days

2007-04-25 19:33:23 · answer #1 · answered by Helmut 7 · 0 0

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