A car traveling at 10 m/s starts to decelerate steadily. It comes to a completer stop in 20 sec. What is its a

Question

A car traveling at 10 m/s starts to decelerate steadily. It comes to a completer stop in 20 sec. What is its acceleration?

Answer 1

Acceleration and deceleration are defined as the change in velocity over time.

Generally, acceleration means that the velocity is increasing over time, while deceleration means that it is slowing.

In your example, the initial velocity of the car V1 = 10m/s. The final velocity of the car is 0 m/s since it comes to a stop.
This change in velocity occurs over 20 seconds.

That is, at
T1 = 0, V1=10m/s
T2 = 20sec, V2 = 0m/s

Acceleration = (V2 - V1) / (T2 - T1)

Plugging in the numbers,

Acceleration = (0m/s - 10m/s) / (20sec - 0 sec).

Acceleration = (-10m/s) / 20 sec = -0.5 m/sec^2

Since the acceleration is negative, it is called a deceleration.

The result means that every second, the velocity of the car is travelling 0.5m/sec slower than it was a second earlier.

Hope this helps,

-Guru

Answer 2

Initial velocity of car 'u'=10 m/s
Final velocity 'v'= zero
time 't'=20 s
acceleration is rate of change of velocity with respect to time.
When acceleration is constant (steady), acceleration=change in velocity / time
=[ final velocity - initial velocity] / time
=[v-u] / t
=[zero -10 ] / 20= -0.5 m/s^2
minus sign indicates retardation.

Answer 3

All of the problems you have posted are the same exact problem. Acceleration is the change in velocity over a change in time.

a = v / t

Use this to solve all of your problems, it is nothing but plug in and calculate.

Answer 4

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