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Silver chloride us very insoluble in water, and by adding a very slight excess of silver nitrate, it is possible effectively to remove all the chloride ion from the sample. First, write the balanced net ionic equation for this reaction. Then assume that a sample has a mass of 1.054 grams contains 21.5% chloride ion by mass. Then calculate the mass of silver nitrate that be used to completely precipitate all the chloride from the sample?

2007-04-25 13:41:28 · 1 answers · asked by Reed 1 in Science & Mathematics Chemistry

1 answers

Ag+ + Cl- -> AgCl

mass of Cl- = .215*1.054 g = 0.2266 g

Mass of AgNO3 = 170*0.2266/35.5 = 1.085 g

2007-04-25 22:24:39 · answer #1 · answered by ag_iitkgp 7 · 0 0

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