The 1/12-scale model of the rocket stood 48 in. high. What was the height of the actual rocket? How?
2007-04-25 13:33:21 · 5 answers · asked by ohhsnap! 4 in Education & Reference ➔ Homework Help
cross multiply 1/12 to 48/x your answer will be in inches..you will have to convet to feet
2007-04-25 13:39:35 · answer #1 · answered by Em W. 4 · 0⤊ 0⤋
The actual rocket would be 12 times 48 inches or 576 inches. You could also say the model rocket is 4 feet tall which would make the actual rocket 48 feet tall.
2007-04-25 13:39:55 · answer #2 · answered by Ej 1 · 0⤊ 0⤋
12x48inches= is the answer
or 12x4feet = is also the answer
or just 48 feet high
or in algabraic terms A X B =C
A being the scale of 1/12
B being the actual height 48 inches
C is the answer 48 feet
2007-04-25 13:48:24 · answer #3 · answered by d.wjohnson 1 · 0⤊ 0⤋
48 feet
2007-04-25 13:38:28 · answer #4 · answered by bwonder48 4 · 0⤊ 0⤋
1/12x=48
multiply both sides by 12
x=576 inches=12 ft high
2007-04-25 13:38:05 · answer #5 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋