Chemistry Homework question PLEASE HELP!?

Question

A student carefully diluted 25.0mL of 6moles/L NaOH solution in 475 mL of distiled water. What is the molarity of the diluted solution base? And why can't the diluted NaOH solution be used as a standard solution of base?


I can't figure this one out. I don't feel like the problem has enough info to solve it.

Answer 1

This is a titration question I think. M1V1 = M2V2
So, it would be:

(6 M)(25.0 mL) = (x M)(475 mL)
x = 0.31 moles

Answer 2

M1 x V1 = M2 x V2

(6.0 M)(0.025 L) = (M2)(0.025 L + 0.475 L)
(0.150 M-L) = (M2)(0.500 L)
(0.150 M-L) / (0.500 L) = M2
0.300 M = M2