The dimensions of cube B are 3 times the dimensions of cube A. If the volume of cube B is 27 cm3, what is the surface area of cube A?
2007-04-25 08:58:58 · 5 answers · asked by hj 1 in Science & Mathematics ➔ Mathematics
The volume of a cube is x^3, where x is the length of one edge. So if the volume of cube B is 27 cm^3, then x = 3 cm.
Next, if the dimensions of cube B are 3 times the dimensions of cube A, then the length of one side of A is 1 cm.
Finally, the surface area of a cube is 6 * x^2, where x is the length of one edge. (x^2 is the surface area of one side, so you multiply by 6 to get the area of all 6 sides.) 6 * (1 cm)^2 = 6 cm^2.
Therefore, the surface area of cube A is 6 cm^2.
2007-04-25 09:06:46 · answer #1 · answered by lord_of_the_squares 2 · 0⤊ 0⤋
If the volume of B is 27 cm3 then its edges are 3 cm each (3 x 3 x 3 = 27)
The dimensions of A are 1/3 that of B so the edge lengths of A are how many cm each? The area of each face would be what? There are how many faces on the cube? Add the area of all of the faces to get the total surface area.
2007-04-25 16:06:40 · answer #2 · answered by dogsafire 7 · 0⤊ 0⤋
the volume of cube B is 27 cm3, each side is cube root of 27 = 3 cm
The dimensions of cube B are 3 times the dimensions of cube A, the side of cube A is 3 / 3 = 1 cm
what is the surface area of cube A? 1 X 1 X 6 = 6 cm2
2007-04-25 16:04:40 · answer #3 · answered by John S 6 · 0⤊ 0⤋
If the volume of cube B is 27 cm3 then each side is 3 cm. When this dimension is divided by 3 it equals one. This means each side of cube A is 1 cm. Each face must be one cm2. Since there are six faces the total surface area is
1 cm2 x 6.
The surface area of cube A is.... 6 cm2.
2007-04-25 16:05:26 · answer #4 · answered by Maestro bestofthebest 2 · 0⤊ 0⤋
surface area of cube A is 6 cm^2
2007-04-25 16:05:22 · answer #5 · answered by Mike 2 · 0⤊ 0⤋