angles to the nearest deg.
plz show me how to do it
2007-04-25 07:34:55 · 4 answers · asked by elona 1 in Science & Mathematics ➔ Mathematics
Do you mean triangle ABC?
If so, then A+B+C=180
so A+20+90=180
A+110=180
A=70
b is the side of the triangle opposite angle B
Use sine to solve for a: sin70=a/10
.9397=a/10
a=9.4
Then use Pythagorean Theorem to solve for c
c^2=a^2 +b^2
c^2= 9.4^2 + 10^2
c^2=88.36 + 100
c^2=188.36
c=13.7
2007-04-25 07:47:37 · answer #1 · answered by Alabama Girl 2 · 0⤊ 0⤋
the sum of the angles in a triangle is 180 degrees.
so A=180-B-C= 70 degrees.
the sin theorem says that a/sinA=b=sinB=c/sinC
b/sinB=c/sinC
=> 10/sin20=c/sin 90
=>c=29.23
pitagora's theorem says that a^2+b^2=c^2 (if C=90 deg)
a=sqrt(c^2-b^2) =27,47
2007-04-25 07:49:06 · answer #2 · answered by ruxacelul 2 · 0⤊ 0⤋
sin20=10/c
c=10/sin20
c=....
a=sqrt(c^2-100)
a=....
angle A=90-20=70
Use your calculator
2007-04-25 07:43:58 · answer #3 · answered by iyiogrenci 6 · 0⤊ 0⤋
wot is that
2007-04-25 07:37:16 · answer #4 · answered by Anonymous · 0⤊ 0⤋