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I need the surface area of a cylinder whose base is 12 inches diamter and 5 inches high.

I also need the surface area of a rectangle with a square base whose length is 12 inches and whose height is 6 inches.

2007-04-25 06:55:13 · 6 answers · asked by Trish7885 2 in Science & Mathematics Mathematics

6 answers

Woah okay lucky for you I just aced this huge test on Surface Area.

Okay, well for the cylinder you have.....

SA=2 O + (rectangle) h
SA=2π r²+ πdh
SA=2 x 3.14 x 6²+3.14 x 12 x 5
SA=414.48in.²

Rectangle.
SA= 2(square) + 2 (square) + 2(square)
SA= 2bh + 2bh + 2bh
SA= 2 x 12 x 12 + 2 x 6 x 12 + 2 x 12 x 6
SA= 576 in²


Hope that helped! But don't stress too hard on it because its not that hard.

Hehehe I'm only in seventh grade.(:

2007-04-25 09:04:08 · answer #1 · answered by Anonymous · 0 0

for the cylinder S=2*pi*r(R+h); r= diamter/2=12/2=6
2 per (3.1416) x 6 inches(6 inches + 5 inches)
Surface= 414 squared inches

and for rectangle
s=Base x height
S= 12 x 6 = 72 squared inches

2007-04-25 07:08:24 · answer #2 · answered by Priam! 1 · 0 0

Question 1
Area of base = π x 6² in² = 36π in²
Area of curved surface = 12π x 5 in² = 60π in²
Surface area = 96π in² = 301.6 in²

Question 2
Surface Area = 2 x (12 x 12) + 4 x (12 x 6) in²
Surface Area = 288 + 288 in²
Surface Area = 576 in²

2007-04-25 07:14:38 · answer #3 · answered by Como 7 · 0 0

S1=132Pi

S2=576

2007-04-25 07:01:52 · answer #4 · answered by bgavra989 2 · 0 0

a) The area of 2 circles is : 2*pi*(6 inches)^2 = 72pi sq. inches
The area of the rest : (12 inches*pi)*5 inches = 60pi sq. inches.
In total, 132pi sq. inches
b)A = 2*(12 inches*12 inches) + 2*(12 inches*6inches) + 2*(12 inches*6 inches) = 576 sq. inches

2007-04-25 07:04:26 · answer #5 · answered by wangsacl 4 · 0 0

Hi ,Do you want to learn by having some one do all your math.You might pick up something while you copy this stuff.YOU know their are formulas for these shapes you have to fine.All you have to do is memorize these formulas and do the math.Come on, you are not that lazy are you?Good Luck

2007-04-25 07:23:44 · answer #6 · answered by rosco 6 · 0 0

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