12m^2 + 48m + 96?

Question

Factor the tinomial if possible, if it cannont be factored then its not factorable.

Answer 1

12(m^2+4m+8)

Answer 2

WOW NOBODY ELSE CAN GET THIS ONE RIGHT? sorry the caps don't entail frustration.. it's just wow

Note that the 1st person's post is not finished, and the 2nd person is wrong...
(It never said solve, nor 12m^2 + 48m + 96 = 0... so it is certainly factor-able.)

12m^2 + 48m + 96...

12(m^2 + 4m) + 96
[12](m^2 + 4m + [4]) + 96 - [48]

12(m + 2)^2 +48
I suppose you can take the 12 out again...
12[(m + 2)^2 + 4]

Answer 3

12m^2 +48m + 96

12 (m^2 + 4m + 8)

m^2 + 4m + 8 is now a simple quadratic problem but you have to solve it using the quadrtic equation if you want to find m

This problem cannot be factored any other way. Than this
12 (m^2 + 4m + 8)

Answer 4

It cannot be factored.

if 12(m^2+4m+8)=12(am^2+bm+c)

so a=1, b=4, c=8
test b^2-4ac= 16-4(4)(8) --> negative
so it cannot be factored

if positive means got 2 factors
equal means got 1 factor only

Answer 5

12(m^2 + 4m + 8)
since delta= b^2- 4ac =4^2- 4x1x8=-16<0
its not factorable

Answer 6

12(m^2 + 4m + 8) =
12(m^2 + 4m + 4 + 4) =
12((m + 2)^2 + 4)

Answer 7

The only common factor is 12
12(m² + 4m + 8) is answer.

Answer 8

It's not factorable.
I can only go to this step
12(m^2 + 4m + 8).
YOu can proceed, if D (b^2-4ac)>=0.

Answer 9

12(m^2+4m+8)

Answer 10

it is not factorable!!!!!!!