What are the chances of getting exactly 5 heads if you flip the coin 10 times. I would like to learn how to get the probability of this? Thanks
2007-04-25 03:37:52 · 4 answers · asked by brian h 2 in Science & Mathematics ➔ Mathematics
You would use a binomial: 252*(.65)^5*(.35)^5=15.35%
The 252 comes from 10c5 (combinations notation).
2007-04-25 03:42:03 · answer #1 · answered by bruinfan 7 · 1⤊ 0⤋
Wow.. I think you need to determine all the possibilities of getting 5 and only 5 heads out of 10 possible coins..
Like, if x is heads, and o is tails then here are some:
xxxxxooooo
xxxxoxoooo
xxxxooxooo
xxxxoooxoo
xxxxooooxo
xxxxooooox
And so on.. now since it is 13/20 to get heads (65%), then it is less likely that only 1/2 of the coins will be heads....
But now I'm lost from there.. but I hope some of this helps
2007-04-25 10:51:57 · answer #2 · answered by cbagan89 2 · 0⤊ 0⤋
You could use the binomial distribution.
Or use logic.
There must be 5 heads and 5 tails.
There are also 10C5 ways of getting 5H and 5T
So P = 10C5 * 0.65^5 * 0.35^5
= 0.1535
2007-04-25 10:44:46 · answer #3 · answered by Dr D 7 · 0⤊ 0⤋
This is a binomial probability:
C(10,5) * (.65)^5 * (1-.65)^5
= 252 * (.65)^5 * (.35)^5
= .154 = 15.4%
2007-04-25 10:42:55 · answer #4 · answered by Kathleen K 7 · 1⤊ 0⤋