I assume that the two vertices on opposite ends of the body diagonal are at (0,0,0) and (1,1,1) to start.
1) Rotate by 45 degrees along x-axis.
Now they are at (0,0,0) and (1/â2, 1/â2, 1).
2) Scale by (2,2,3).
Now they are at
(2, 2, 3)*(0,0,0) = (0,0,0)
and
(2, 2, 3)*(1/â2, 1/â2, 1) = (â2, â2, 3).
3) Translate by (0,-2,3).
Now they are at
(0,0,0) + (0, -2, 3) = (0, -2, 3)
and
(â2, â2, 3) + (0, -2, 3) = (â2, -2+â2, 6)
The two vertices on opposite ends of the body diagonal are at (0, -2, 3) and (â2, -2+â2, 6).
The other six can be readily determined from these two.
2007-04-25 05:30:52
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answer #2
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answered by Northstar 7
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