English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

3 answers

a=6
b= -5
c=3


formula:
[-b+-(b^2 - 4ac)^1/2]*(1/2a)

note : [square root of (b^2 - 4ac)]

sub it in and ull get 2 ans for x

x=0.98797 , -0.15464

2007-04-24 22:07:09 · answer #1 · answered by espresso 6 · 0 0

6x^2 + 3 = 5x
6x^2 - 5x + 3 = 0
a = 6
b = -5
c = 3

x =( -b +/- sqrt b^2 - 4ac)/2a
x = ( - (-5) +/- sqrt 5^2 - 4(6)(3))/2 (6)
x = (5 +/- sqrt 25 - 72)/12
x = 5 +/- sqrt -47/12
Evaluate +/- sqrt -47 to get exact answer
x has two values

2007-04-24 23:11:58 · answer #2 · answered by detektibgapo 5 · 0 0

6x² - 5x + 3 = 0
x = [5±√(- 47)] / 12
x = [5 ± i √47] / 12 is exact solution.
If √47 is calculated, solution becomes approximate.

2007-04-24 22:15:18 · answer #3 · answered by Como 7 · 0 0

fedest.com, questions and answers