how many grams of the second listed reactant is needed to react completely with1.772g of thefirst listedreact?

Question

si02+3c-->2c0+SiC

Answer 1

Answer: 1.063 g of Carbon

Molecular Mass:
SiO2 = 60.0848 g/mol
Carbon = 12.011 g/mol

First, find the number of moles of SiO2.
1.772 g / 60.0848 g/mol
= 0.02949 mol SiO2

As you can see from the balanced equation, for every mole of SiO2, you need 3 moles of Carbon.

(0.02949 mol SiO2) * (3 mol Carbon/ 1 mol SiO2)
= 0.08847 mol Carbon

To get the mass of Carbon needed, multiply the number of moles by molecular mass.

(0.08847 mol Carbon) * (12.011 g/ 1 mol Carbon)
= 1.063 grams of Carbon

So for 1.772 g of SiO2 to react completely, you need 1.063 grams of Carbon.

Answer 2

The first reactant is Silicon Dioxide (Molar mass = 60)

Second reactant is Carbon (Molar mass = 12)

So, with 1.772 g of SiO2, C = 60*1.772/36

= 2.95 g