2007-04-24 19:10:35 · 7 answers · asked by SC 2 in Sports ➔ Baseball
Always having a winning team in the regular season isn't difficult to be a fan of, but maybe when teams don't live up to expectations in the postseason?
2007-04-25 02:38:01 · update #1
It's not hard if you live near NYC or Boston. You're born into it and your born into the rivalry as well.
Spoken as a Yankee fan.
2007-04-25 00:58:42 · answer #1 · answered by Oz 7 · 1⤊ 0⤋
I'm a Kentucky basketball fan and an Oakland A's fan (grew up in Cali, live in Lexington), and I'll say it's harder to be a UK fan because when they lose 5 games it's VERY frustrating, while Oakland can go 15 years without a World Series and it's just now starting to get old. Expectations will kill. When you expect to win it all, anything less is a disappointment. That being said, it must be pretty hard to be a soulless louse and root for Jeter, A-Rod and the rest of those cellar-dwellin' Yanks! (At this point, Yankees fans should just pray that at some point this year they'll have more wins than A-Rod has home runs!)
2007-04-25 06:53:56 · answer #2 · answered by schmogden 2 · 1⤊ 1⤋
Being a red sox fan is great. It's tough because you never know whats going to happen when these 2 teams play. But I cant lie, I love to HATE the yankees :)
2007-04-25 03:08:11 · answer #3 · answered by jprincesa85 1 · 1⤊ 0⤋
I love being a Red Sox fan. However, I do get frustrated when they put the likes of Tavaras in the starting rotation. He is and has ALWAYS been a minor league pitcher. He is an albatross in an otherwise great rotation.
Chow!!
2007-04-25 06:15:27 · answer #4 · answered by No one 7 · 0⤊ 0⤋
Neither Yankees or Red Sox fans have long finger nails. Enough said?
2007-04-25 02:32:57 · answer #5 · answered by liberty11235 6 · 1⤊ 2⤋
I love the Yankees and I live in Boston. Figure it out.
2007-04-25 02:20:53 · answer #6 · answered by witchette 3 · 1⤊ 0⤋
Its not tough at all...us die hard fans like to complain cause thats what we do.
2007-04-25 02:46:13 · answer #7 · answered by poppa flash 2 · 1⤊ 0⤋