How do I find the solutions for x²+2x=5 ?

Question

Can someone please tell me the correct answer and the steps for solving it?

Answer 1

x^2 + 2x = 5 first thing u wanna do is factor out an x which gives us...
x(x + 2) = 5 now set both equal to 0 that is
x = 0 this is one solution and
x + 2 = 5 and solve for x and this will be ur second solution
x + 2 = 5 subtract 2 from both sides to get
x = 3

So your answer is x = 0 and x = 3.

if you need more help or further clarification email me or im me. Good Luck.

Answer 2

First of all, this equation has to be put into the correct format before it can be factorised.
The correct format is ax + bx + c = 0
So the equation should be re-written as x² + 2x – 5 = 0
Then this formula has to be used in order to solve the equation:
X = (–b ± square root of b² – 4ac) ÷ 2a
So a = 1, b = 2, and c = –5…then plug these values into the above formula:
X = [–2 ± square root of (–2)² – 4(1)(–5)] ÷ 2(1)
X = [–2 ± square root of 4 + 20] ÷ 2
X = [–2 ± 2 + 20] ÷ 2
X = [–2 ± 22] ÷ 2

So this implies that u are going to end up with 2 solutions:
Solution 1: [–2 + 22] ÷ 2 = 20 ÷ 2 = 10
Solution 2: [–2 – 22] ÷ 2 = –24 ÷ 2 = –12

So x = 10 and x = –12...and they’re the solutions! Hope this helps! =)

Answer 3

x^2 + 2x = 5
x^2 + 2x + (2/2)^2 = 5 + (2/2)^2
( x + 1 )^2 = 5 + 1
( x + 1 )^2 = 6
x + 1 = Square root of 6
x + 1 = 2.4495
So,
Let x + 1 = 2.4495
x = 2.4495 - 1
x = 1.4495

Let x + 1 = - 2.4495
x = -2.4495 - 1
x = -3.4495

therefore , x = 1.4495 or -3.4495

Answer 4

Subtract 5 from both sides to get x^2+2x-5=0 This doesn't factor, so you must use the quadratic formula, with a=1, b=2, and c=-5

-b+/-sqrt(b^2-4ac) / 2a
-2+/-sqrt((-2)^2-4(1)(-5)) / 2(1) (plug in numbers)
-2+/-sqrt24 /2 (evaluate inside square root)
-2+/-2sqrt6 /2 (simplifying square root)
-1+/-sqrt6 (divide by two)

So your two answers are -1+sqrt6 and -1-sqrt6

(Make sure you check your solution by plugging it back into the original equation). (The guy above me is totally wrong.)Hope this helps!! =)

Answer 5

First off, re-write it in standard quadratic form
x²+2x-5=0 and then use the quadratic formula (since it won't factor 'nicely')
x = (-2 ±√(4-(-20)))/2 Now...... You do the arithmetic so you'll remember it ☺


Doug