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A couple has two kids. One kid has albinism and one is normal. What genotype pair can the parents NOT be? A=normal and a=albinism.


Aa x Aa

Aa x AA

Aa x aa

All of pairs could produce both normal and albino kid?

2007-04-24 17:50:20 · 5 answers · asked by Anonymous in Science & Mathematics Biology

5 answers

Because one child has albinism (aa), that means that each parent must have a lower-case a.

That rules out the second choice Aa x AA.

The first and third choices are both possible.
Try the Punnett squares, and you'll see.

2007-04-24 17:56:15 · answer #1 · answered by ecolink 7 · 0 0

1st and 3rd could produce an albino.
2nd cannot. Use punnett square to figure.

If cross Aa X AA and albinism is recessive, then there is no way these parents can have an alibino child.
They would produce either: AA or Aa children. 50% chance of producing either one. Both parents must contain the recessive "a" to have an albino.

2007-04-24 17:57:59 · answer #2 · answered by AT 3 · 0 0

If memory serves from genetics many years ago, Aa x AA could not produce both a normal and an albino child.

2007-04-24 17:53:55 · answer #3 · answered by Anonymous · 0 0

the mummy is heterozygous for albinism. a hundred% of the youngsters are companies. 50% of them may be heterozygous and characteristic a classic phenotype, the different 50% may be albino (homozygous for the recessive trait).

2016-10-30 05:54:47 · answer #4 · answered by ? 4 · 0 0

Aa x AA as you need 2 copies of aa...this will not give you that result (only Aa, AA, Aa AA)
THe others will give you aa's in those crosses
Aa x Aa will give AA, Aa, Aa aa (25% chance of albinism)
while
Aa x aa will give Aa, aa,Aa, aa so 50% chance of albism (and 50% will be carriers)

2007-04-24 17:57:29 · answer #5 · answered by mareeclara 7 · 1 0

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