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∫1/(x+x^(4/5)) dx

Let u=x^(1/5). Then du=1/5 x^(-4/5) dx, and dx = 5 u^4 du. So this becomes:

∫5 u^4/(u^5 + u^4) du

Canceling:

∫5/(u+1) du

Which integrates easily as:

5 ln |u+1| + C

Resubstituting, we have:

5 ln |x^(1/5) + 1| + C

And we are done.

Edit: Oops! I forgot the constant 5 the first time around. Sorry about that. The integral is correct now.

2007-04-24 16:07:57 · answer #1 · answered by Pascal 7 · 1 0

its been awhile for me too, but i have an idea that might work. factor the denominator and use partial fraction decomposition to break in down and then integrate the pieces. (if you try it let me know if it works out)

2007-04-24 16:07:58 · answer #2 · answered by en garde 3 · 0 0

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