2007-04-24 15:59:59 · 5 answers · asked by MaRiNa 2 in Science & Mathematics ➔ Mathematics
3x^2=5x
3x^2 - 5x =0
x(3x - 5) = 0
x=0, and x = 5/3
2007-04-24 16:03:40 · answer #1 · answered by fcas80 7 · 0⤊ 0⤋
3x^2 - 5x = 0
x (3x - 5)= 0
so, x =0 and x = 5/3
2007-04-24 23:06:02 · answer #2 · answered by sporty_gurly_13 5 · 0⤊ 0⤋
3x^2 = 5x
Move terms to one side of equation.
3x^2 - 5x = 0
Factor out an x.
x(3x - 5) = 0
Set each factor equal to zero and solve
x = 0
3x - 5 = 0
3x = 5
x = 5/3
Your solutions are 0 and 5/3
2007-04-24 23:03:57 · answer #3 · answered by suesysgoddess 6 · 2⤊ 0⤋
3x^2=5x
Divide both sides by x
3x=5
Divide by 3
x=5/3
2007-04-24 23:04:36 · answer #4 · answered by Josh 3 · 0⤊ 0⤋
x(3x-5)=0
x=0
3x-5=0
x=0,5/3
2007-04-24 23:04:28 · answer #5 · answered by climberguy12 7 · 0⤊ 0⤋