can somebody please help me with these math problems??

Question

x^2 = - 16


5y^2 = - 40


r^2 - 4 = -8


-2t^2 - 8 = 46


3x^2 + 1 = -35


y^2 + 25 = 0

Answer 1

uhhh X is not a real number in this case. All the equations would require you to take a square root of a negative number and thats not possible.

Answer 2

for x^2 = -16 what you have to do is solve for x. so to get x by itself for this problem, you would find the square root of x and because what you do to one side you do to the other, you also find the square root of -16. so your next line of work should show x=√-16. since negatives numbers dont have square roots there is no solution, unless you're using imaginary numbers. where i = √-1. so what you do would be take out i and you get x=(√16)i which simplifies into x=4i or -4i.(becase both -4 and 4, when squared equal to 16) and for the others like the second one just follow the same steps. excet first simplify both sides. divide both by the coeffecient, 5 and you get y^2 = -8 and then find the square root of both sides. y=√-8 which again is impossible unless dealing with imaignary numbers. which would be y= (√8)i. sorry for the long explanation but hope it helps.

Answer 3

ok
1. take the square root of -16 which is 4i
2. divide -40 by 5 to get -8 then take the square root = the square root of eight or in simpler terms 2 root 2i
3.add 4 to -8 to get -4 take the square root to get 2i
4. add 8 to 46 to get 54 then divide by -2 to get -27 then take the square root of -27 which is reduced to 3 root 3i
5.add 1 to get -36 divide by 3 to get -12 then take the square root to get 2 root 3
6. =5i the square root or -25 is 5i

Answer 4

x^2=-16 (square root both sides to get x isolated), comes to x=-4
5y^2=-40 (divide both sides by 5 which gives you y^2=-8, which comes out to the square root of negative 8)
r^2-4=-8 (add 4 to both sides, results in r^2=-4, square root to get r=-2)
-2t^2-8=46 (add 8 to both sides, -2t^2=54, divide both sides by 2 to get -t^2=54, square root both sides, comes out to the square root of -54)
3x^2+1=-35 (subtract 1 from both sides, 3x^2=-36, divide both sides by 3 to get x^2=-12, x=square root of -12
y^2+25=0 (subtract 25 from both sides, y^2=-25, square root both sides to get y=-5.

Answer 5

4
2i root 2
2i
3i root 3
2i root 3
5i

Answer 6

hm. if you havent done imaginary numbers yet, then they are all no solution, but if you have, here
1. +-sqrt-16=x correct?
+-sqrt-16=x=isqrt16
x=4i,-4i
2. y=+-sqrt-8
y=2isqrt2,-2isqrt2
3. r=+-sqrt-4
r=2i,-2i
4. t=+-sqrt-27
t=3isqrt3,-3isqrt3
5. x=+-sqrt-12
x=2isqrt3,-2isqrt3
6. y=+-sqrt-25
y=5i,-5i
the other two people are incorrect