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1. what is the concentration of a household (NH4OH) cleaning soln in 49.90mL of .590M HCl is required to neutalize25.00mL soln?
2. given 238ml of sulfuric acid, find moarity when 34.2mL of lithium hydroxide is used to titrate 15.0mL of the acid?

2007-04-24 15:38:45 · 1 answers · asked by a.h. 2 in Science & Mathematics Chemistry

1 answers

1. I think you mean that 25 mL of the ammonia solution is neutralized by 49.4 mL of 0.59 M HCl.
The neutralization reaction is
[NH4OH]+HCl -> NH4Cl + H2O.
This tell us that for each mole of ammonia in solution, 1 mole of HCl will neutralize it.
So how much HCl do we have?
(49.9/1000 ml/L) x 0.59 M = 0.03 moles.
What the molar conc of the cleaning solution
0.03 moles = (25/1000) x [NH4OH]
Molar coc = 1.2 Molar appx
2. NoCanDo. You need a molality of something. check your problem again.

2007-04-24 15:50:37 · answer #1 · answered by cattbarf 7 · 0 0

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