I have trouble finding the definite integrals?

0 ⤊

1. 1/(sqrt(2x+1)) , lower limit: 0 , upper: 4
2. sqrt(2x+1) , lower limit: 0 , upper: 4
This should be easy, but i cant get the correct answer!
Thanx

2007-04-24 15:24:02 · 2 answers · asked by bojandzukovski 3 in Science & Mathematics ➔ Mathematics

1.
2 (2x+1)^(1/2) = 6

2.
2/3 (2x+1)^(3/2) = 18

2007-04-24 15:30:31 · answer #1 · answered by boo0726 3 · 0⤊ 0⤋

Int 1/(sqrt(2x+1) dx = sqrt(2x+1)(between (0,4)=3-1=2
Int(sqrt(2x+1) dx = (2x+1)^3/2 * 1/3 (0,4)=9-1=8

2007-04-24 22:34:06 · answer #2 · answered by santmann2002 7 · 0⤊ 0⤋