I need help calculating the surface area which is very hard for me. my teacher told me its okay if you gize can answer my question like give me the answer. Um... but she said you gize need to ezplain it to me descriptivly. Um.. the question is what is the surface area of a box 6 feet long, 4 feet wide and 8 feet high??? Thank you so much everyone I really appreciate it. if you can answer my question.
2007-04-24 14:35:49 · 3 answers · asked by Sarina D 3 in Science & Mathematics ➔ Mathematics
The surface area of a polyhedron is simply the sum of the areas of its sides. A box has six sides. Let ℓ be the length of the box, w be the width, and h the height. The top and bottom sides are ℓ×w rectangles, the front and back sides are ℓ×h rectangles, and the left and right sides are w×h rectangles. So the sum of the areas of these rectangles is 2ℓw + 2ℓh + 2wh. Substituting the given values:
SA = 2*6*4 + 2*6*8 + 2*4*8 = 208 ft.²
2007-04-24 14:53:09 · answer #1 · answered by Pascal 7 · 2⤊ 0⤋
Sure why not.
SA = 2(ab) +2(ac)+2(bc)
or
SA = 2(6*4)+2(4*8)+2(8*6)
Now use BEDMAS
2(24) + 2(32) + 2(48)
Now add
48 + 64 + 96
= 208ft^2
Surface Area of a Rectangular Prism = 2ab + 2bc + 2ac
2007-04-24 21:49:24 · answer #2 · answered by thealphadude1992 2 · 1⤊ 0⤋
A box has 6 sides.
2 sides have areas of (length*wide).
2 sides have areas of (length*height).
2 sides have areas of (wide*height).
Total surface area = 2(length*wide) + 2(length*height) + 2(wide*height)
= 2(6*4) + 2(6*8) + 2(4*8)
= 2(24) + 2(48) + 2(32)
= 48 + 96 + 64
= 208 feet square
2007-04-24 21:47:14 · answer #3 · answered by QiQi 3 · 1⤊ 0⤋