Please help me balance these equations!?

Question

1. H2 + O2 -> H20
2. S8 + O2 -> SO3
3. HgO-> Hg +O2
4. Zn +HCl -> ZnCL2 + H2
5. Na + H2O -> NaOH + H2

Answer 1

1. 2H2 + O2 -> 2H20
2. S8 + 12O2 -> 8SO3
3. 2HgO->2 Hg +O2
4. Zn +2HCl -> ZnCL2 + H2
5.2Na +2H2O ->2NaOH + H2

Answer 2

Balancing follows fairly simple rules:
The lowest coefficient of a chemical is 1
The sum of coefficients x subscipts of each element on the reactant side must equal the sum on the other side.

With that in mind:
#1. We have 2 oxygens on the left, but one on the right. We can double the H2O on the right, but this gives us 4 H on the right. To balance this, we double the H2 on the left.
2H2+ O2 -> 2 H2O
#2 We have 8S on the left but 1 on the right. We can make the right hand side 8SO3, but this gives us 24 O. 12O2 can supply this.
S8 + 12O2 -> SO3
#3 We have 2O on the right, so we need to double HgO. Now we have 2 Hg on the left and one on the right, so we double the Hg on the right.
2 HgO -> 2Hg + O2
You should have the hang of this by now.

Answer 3

1. 2H2 + O2=2H2O 2. S8 + 12O2=8SO3
3. 2HgO >2Hg +O2
4. Zn+2HCl>ZnCl2 + H2
5. 2Na + 2H2O>2NaOH +H2

Answer 4

1. 2H2 + O2 -> 2H2O
2. S8 + 12O2 -> 8S03
3. 2HgO -> 2Hg + O2
4. Zn + 2HCL -> ZnCl2 + H2
5. 2Na + 2H2O -> 2NaOH +H2

Answer 5

1.H2+O2->H2O
6H2+3O2->6H2O 5.NA+H2O->NaOH+H2
2.S8+O2->SO3 can't be done. 2Na+2H2O->2NaOH+H2
2S8+3O2-> 2S8O3
3.Hgo->Hg+O2
2HgO->2Hg+O2
4.Zn(ll) +HCl->ZnCl2+H2
Zn+2HCl->ZNCl2