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I have 5 grams of CU and 25 Degrees Celsius right now... after injecting 5,000,000 KJ of heat energy what is the final temperature?

here is the information about CU required to solve it..
ΔH (Fussion) - 1326 KJ/Mole
Melting Point - 1085 Degrees Celsius
Specific Heat Capacity - 24.4 J/Mole degree C
ΔH (Vap) - 300.4 KJ/Mole
Boiling Point - 2562 degrees celsuius

2007-04-24 13:29:44 · 1 answers · asked by Abdul S 3 in Science & Mathematics Chemistry

1 answers

(5/63.55)(0.0244(1085 - 25) + 1,326 + 0.0244(2,562 - 1,085) + 300.4 + 0.0244(T - 2562)) = 5*10^6
(0.0244(1060) + 1,326 + 0.0244(1,477) + 300.4 + 0.0244(T - 2562)) = 63.55*10^6
(0.0244(1060 + 1,477 + T - 2562) = 6.35483736e+7
T - 25 = 2.6044415409836065573770491803279e+9
T = 2,604,441,566°C

2007-04-26 19:10:34 · answer #1 · answered by Helmut 7 · 0 0

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