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I had to make a box that was 22,400 cubic centimeters and now I have to calculate the mass and volume of Helium that would fill that box. How do u do it?

2007-04-24 13:16:15 · 3 answers · asked by Anonymous in Science & Mathematics Chemistry

3 answers

Simple...read your textbook. That's what it is there for...it's called learning.

2007-04-24 13:23:25 · answer #1 · answered by Anonymous · 0 0

Ideal gas law: PV = nRT. The volume of helium that fills the box is the volume of the box. So the problem reduces to mass. The gas law gives you n, the number of moles. You multiply by 4 g/gmole to get weight. I assume P will be about 1 atm. V = 22.4 L. T= temp in room in deg K. R= 0.082 atm-L/mole-degK.

2007-04-24 20:25:25 · answer #2 · answered by cattbarf 7 · 0 0

22400 cm3= 22.4 L
One mole of a perfect gas occupies 22.4L at 0°C
one mole of helium weighs 4.00g
It's from the perfect gas law: PV=nRT

2007-04-24 20:27:05 · answer #3 · answered by marie9 5 · 0 0

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