How much work is done to transfer 0.15 C of charge through an electric potential difference of 9.0 V?

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How much work is done to transfer 0.15 C of charge through an electric potential difference of 9.0 V?

Please help me with this problem.
I don't understand it.

2007-04-24 12:41:15 · 4 answers · asked by vicky p 1 in Science & Mathematics ➔ Physics

4 answers

V = E * d

E = F/q

V = F/q * d

V = (Fd)/q

Fd = work

V = work/q

9 = work / .15
work = 1.35 J

hope this helps

2007-04-24 12:49:51 · answer #1 · answered by 7 · 1⤊ 1⤋

0.15 C = 0.15 As (1 C is the charge of a 1 A current during 1 second)

Amount of work done is amount of energy = charge * voltage.

0.15 C * 9.0 V = 1.35 VAs = 1.35 Ws = 1.35 J.

2007-04-24 13:01:43 · answer #2 · answered by oneinunity 4 · 0⤊ 0⤋

Work = Energy = q*V; so the total work is 0.15*9 = 1.35 joules.

2007-04-24 12:46:09 · answer #3 · answered by gp4rts 7 · 0⤊ 0⤋

WD = Q x V just multiply to get answer in joules

2007-04-24 12:44:33 · answer #4 · answered by hello 6 · 0⤊ 0⤋