Question is: to Calculate the power which is supplied by current source, by using nodal analysis?

Question

please see this link http://sit.edu.pk/question/Mesh%20Analysis_Q1.doc

Answer 1

Summing voltages around the left loop,
I1*4=4 I1=1mA


Summing voltages around the voltage supplies and the 6kohm resistor
I2*6=10+4
I2=14/6 mA
The voltage across the 2A current source is
14=V2+12000*2
(this is way out of whack since the current from the current source is huge compared to the resistor sizes. 2mA would make so much more sense)
So 2A through 12 kohm is 24kV

If the current source were 2mA, the voltage would be 24 V, and the voltage across the current source would be -38 V, and power would be 38*2=76 W

Since the diagram shows 12 kohm, the voltage across the 2A current source would be
24,014 V and power is times current
48,028 W

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Answer 2

This is tough to do without drawing. Pick a ground node arbitrarily. (I'll use the bottom).

Upper left corner is at 4 volts. Use that and ohm's law to get the current going down the 4 kiloohm resister.

Therefore, to the right of the 10V source has to be 14V. Use that to calculate the current going down the 6 kiloohm resistor.

You know the current going through the2A current source (duh).

Then just use the branch law to calculate current through the batteries. The big battery will have the 6 kiloohm resistor current less 2 amps. The small battery will have the big battery's current plus the 4 kiloohm resistor current.

Power = Current * Voltage
Do that for each battery to get power.

One more step to get the current source's power. You have to calculate the voltage drop of the resistor above it (using ohm's law). Subtract that from the 14V on the hot end of the 10V battery and you have the voltage drop across the current source.

Power = Current*Voltage

Have fun!

Answer 3

replace each and each voltage source in turn with that's inner resistance (or a short circuit) then use the universal of superposition to exercising consultation what takes position even as both sources are in position. short out V2 and calculate Vn (call it Vn1) by V1 short out V1 and calculate Vn (call it Vn2) by V2 Then Vn = Vn1 + Vn2 something is trivial.