What stops singularities (infinite mass) of black holes effecting all matter in the universe equally?

Question

I have a limited knowledge of particle physics, yet, I understand that theoretically the range of a graviton is infinite, and the mass of the singularity of a black hole is infinite. I also understand that (theoretically) the effect of gravity is created by the exchange of gravitons and the chance of exchange is greater at smaller distances and greater mass (this is what creates the effect of gravity, am i right?)

So my question is, what stops the singularity of a black hole that is said to have infinite mass, exchanging an equal amount of gravitons with all matter in the universe, thus all matter experiences the same pull as that which is entering the event horizon? Is there a fundamental idea with gravitons, or gauge bosons in general that I am missing, or is my idea on such particle physics completely wrong? Thanks.

Answer 1

The inverse square law. Gravity twice as far away is 1/4 as strong. At a distance of millions of miles, you cannot tell the difference between a normal star and a black hole of the same mass. But because the black hole with the same mass as the star is MUCH smaller than the star, you can approach it more closely without hitting the surface, and every time you cut the distance in half, gravity gets 4 times stronger.

A singularity does NOT have infinite mass, it has infinite DENSITY. And since the distance used in the inverse square law is from the center of mass and not the surface, the gravity of a normal mass with medium density, like a star, is limited by the volume of space occupied by the mass. You cannot get closer to the center than the surface of the star. But compress that star into an infinitely small volume and you get infinite density and can approach infinitely close. And using the inverse square law, 1/distance goes to infinity as distance goes to zero. So a black hole behaves no different than any other object of the same mass as long as you don't get really close.

Answer 2

A singularity has a quantity of 0. Any non-0 mass crunched right down to a quantity of 0 could have countless density (even if, its mass continues to be finite). Take a finite mass. That mass has a Schwarzchild radius. If the whole mass no longer directly shows itself interior this radius, then the exterior international basically interprets it as a black hollow. It nonetheless has the comparable mass (the mass would not improve because of the fact it went interior the progression horizon). even if, all of us understand of no mechanism which could postpone the mass against its very own gravity as quickly because it has exceeded interior the progression horizon. Plus, we determine that area and time behave in yet in a various way interior. consequently, each little thing behaves as though all the mass have been in a singularity. If dealing with a black hollow, continuously deal including your equations as though the mass exchange right into a singularity. no longer directly, it continuously works. Is it particularly continuously a singularity? We had very "excited" discussions for the period of my recent path.

Answer 3

I know nothing about this, but is infinite really infinite.

I rememer from undergrad calc that as something approaches infinity it is all the same.

So, can infinite mass of a black hole be a whole lot less than the infinite mass of the universe?

Just trying to help and do my part.

Answer 4

Black holes most definitely do NOT have infinite mass. I'm not sure where you got that idea.

The reasons that all matter in the universe is not affected by a black hole is distance and the finite value for the speed of light.

Answer 5

I think you should look at it more closely as the bending of the space-time continuum instead of gravitons. Think of a bedsheet you drop a bowling ball on. The closer you get to the bowling ball, the more the effect on space-time. Of course this is a simple metaphor.