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What mass of aluminum chloride (133.33 g/mole) can be produced by reacting 4.0 mols of aluminum (26.98 g/mol) with hydrochloric acid (36.46 g/mol)?

2Al+ 6HCl yeilds 2AlCl3 + 3H2

2007-04-24 08:42:28 · 2 answers · asked by Cameron 1 in Science & Mathematics ➔ Chemistry

2 answers

The ratio of Al to AlCl3 is 1 : 1

4.0 mol Al will produce 4.0 mol AlCl3

mass = moles x molecular mass

4.0 moles x 133.33 g/mole = 533.32 g AlCl3

2007-04-24 08:48:07 · answer #1 · answered by physandchemteach 7 · 0⤊ 0⤋

If HCl is in excess

2 moles Al >> 2 moles AlCl3

we get 4.0 moles AlCl3

4 x 133.3 =533 g AlCl3

Besides I thing you forgot the moles or the grams of HCl

2007-04-24 08:48:17 · answer #2 · answered by Non più attiva su answers 7 · 0⤊ 0⤋