2n(n-20)=0?

Question

Solving Quadratic Equations by Factoring

Answer 1

2n(n-20) = 0

This can be broken down into two parts

2n = 0 and n - 20 = 0

2n = 0
then n = 0

n - 20 = 0
then n = 20

Therefore the quadratic equation has two solutions:

n = 0

and n = 20

Answer 2

well rei is japanese for zero. so the equation is equal to you.
2n(n-20) = 0 = Rei = you so you make n whatever the heck you want it to be.
lol but yeah either 2n = 0 or n - 20 = 0, because you're multiplying two numbers and having a product of zero. if 2n is zero then n is 0. if n - 20 is zero then n is 20.

Answer 3

so 2n=0 or (n-20)=0 (anything multiplied by 0 is always 0)
so n=0 or n=20

Answer 4

2n(n-20)=0
2n^2-40n=0
2n^2=40n
2n=40
n=20