2007-04-24 07:41:15 · 7 answers · asked by christy r 1 in Science & Mathematics ➔ Physics
Density = 0.75 gm/cc.
As it displaces 3/4 of its Volume in water.
2007-04-24 07:45:23 · answer #1 · answered by Anonymous · 2⤊ 0⤋
If V is the volume of the log, 3/4 th of volume is inside the water and the mass of the displaced water is equal to the mass of the log. So, the density of the log is 0.75 g/cc assuming that the density of water is 1 g/cc.
Mass of the water displaced = Mass of the log
3V/4 grams = V X density of log
So, density = 3/4 grams = 0.75
2007-04-24 07:49:59 · answer #2 · answered by Swamy 7 · 1⤊ 0⤋
Let d (kg/m³) be the density of wood, V (m³) be the total volume of the log, the mass of the log, in kilograms, would be m = Vd The mass of water displaced by the immersed log's volume is m' = (1 - 0.47)Vd' = 0.53Vd', where d', the density of water, is equal to 1000 kg/m³ m' = 530V The log is floating when its mass is equal to the mass of water it displaces m = m' Vd = 530V d = 530 kg/m³
2016-05-17 22:15:39 · answer #3 · answered by ? 3 · 0⤊ 0⤋
The density of the log is 0.75 gm/cc assuming that the river has pure water.
2007-04-24 07:50:37 · answer #4 · answered by Scott H 3 · 1⤊ 0⤋
It depends on the purity of the river water -- which impacts the specific gravity of the water and thus effects the calculation of the floating object's density.
2007-04-24 07:46:00 · answer #5 · answered by MB 4 · 1⤊ 0⤋
Specific gravity of 3/4. It would be 1 if it weighed exactly the same as the same volume of water, and greater than 1 if it sank.
2007-04-24 07:46:08 · answer #6 · answered by freeetibet 4 · 1⤊ 0⤋
SURFACE AREA???
How long is the log? by what width?
And if you don't wanna do it that way... It's just BS stuff that you are reading off a book
So don't even bother
2007-04-24 07:45:27 · answer #7 · answered by Anonymous · 0⤊ 3⤋