Equations of Lines?

Question

I need to know the slope-intercept form of the equation passing through the points (-3, 4) and (3, 6).

Answer 1

First, find the slope...

m = (y2 - y1) / (x2 - x1)
= (6 - 4) / (3 - -3)
= 2 / 6
= 1/3

Now, pick one point and use the point-slope formula

y - y1 = m(x - x1)

y - 6 = (1/3)(x - 3)
y - 6 = (1/3)x - 1
y = (1/3)x + 5

Answer 2

OK, first, find the slope:

m = (y1 - y2)/(x1 - x2) = (6 - 4)/[3 - (-3)] = 2/6 = 1/3

Then write the equation as:

y = (1/3)x + b

Plug in the x and y values from wither point (I'm choosing the second one) and solve for b:

6 = (1/3)(3) + b
6 = 1 + b
b = 5

Now that you know m and b, just write the equation as your answer:

y = (1/3)x + 5

Answer 3

y-4=(6-4)/(3+3)(x+3)
By solving
y=x/3+5

Answer 4

m = (6 - 4) / (3 + 3) = 1 / 3
Line passes thro` (3,6)
y - 6 = (1/3).(x - 3)
y = (1/3).x + 5

Answer 5

y = 1/3x + 5