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are the following:
-bounded or unbounded??
-convex sets or not convex sets??

a)
[ ( x , y ) І x + y ≤ 1, x - y ≤ 2 , x ≥ 0 ]

b)
[ ( x , y ) І ІxІ ≤ 1, Іx - 3І ≤ 2 ]

c)
[ ( x , y ) І x² + y² ≤ 1 and x² + (y² + 1) ≤ 1 ]

d)
[ ( x , y ) І (x - 2)² + y² ≤ 1 or x - y ≤ 0 ]

cheers for your help!!

2007-04-23 22:53:20 · 3 answers · asked by Fred B 1 in Science & Mathematics Mathematics

3 answers

a) I assume you meant to include "and".

[ ( x , y ) І x + y ≤ 1 and x - y ≤ 2 and x ≥ 0 ]

This is bounded and convex.

b) I assume you meant to include "and".

[ ( x , y ) І ІxІ ≤ 1and Іx - 3І ≤ 2 ]

-1 ≤ x ≤ 1

-2 ≤ x - 3 ≤ 2
1 ≤ x ≤ 5

Solution set is the line x = 1.

This is unbounded. I don't think convex / not convex applies to a line.

c)
[ ( x , y ) І x² + y² ≤ 1 and x² + (y² + 1) ≤ 1 ]

These are two partially overlapping circles.

This is bounded and convex.

d)
[ ( x , y ) І (x - 2)² + y² ≤ 1 or x - y ≤ 0 ]

The second condition contains the first so this is just the half-plane

x - y ≤ 0

This is unbounded.

2007-04-23 23:13:39 · answer #1 · answered by Northstar 7 · 1 0

The above answer proves plenty greater suitable than what you like. Any functionality on the airplane with non-supply up by-product is lipschitz on bounded contraptions. Follows from the definition and integration on segments. that's it.

2016-10-28 20:02:45 · answer #2 · answered by Anonymous · 0 0

I'm sorry...does this question involve Rosalind Russell???

...whoops...my mistake...

2007-04-23 22:56:49 · answer #3 · answered by hez b 3 · 0 2

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