Solving Equations by Factoring?

Question

3x² + 7x = -2
1/3, 3
3, 2
-2, -1/3

2: x² - 49 = 0
-7, 7
7
-7

3: x2 + 5x + 4 = 0
4, 1/4
-1, -4
-4, 1

4: 6x2 - 2 = x
-1/2, 2/3
-1, 2/3
2, 1/2

5: x2 - x = 42
-7, 6
6, 7
7, -6

6: x² - 21x - 72 = 0
24, -3
3, 24
8, -3

7: 7x² - 7x - 2x + 2 = 0
1/7, 2
2/7, 1
-2, 2/7

8: 3x² - 2x - 5 = 0
5/3, 1
5/3, -1
1, 3/5

9: 2a² - 9a = 5
5
1, 5
-1/2, 5

10: 33x² - x - 14 = 0
2/3, -7/11
3/2, -7/11
2/3, 7

11: 21x² + 22x - 24 = 0
-4/3, 5/7
-2/3, -12/7
2/3, -12/7

12: 2x2 + 2x = 60
5, -6
6, -5
-3, 5

13: x2 + 16x + 48 = 0
-3, 4
4, 12
-4, -12

14: x3 - x2 - 12x = 0
-3, 4, 0
2, 4, 6
-2, 3, 0

15: 4x² + 8x + 4 = 0
-2
-1
1, 2

Answer 1

Hi,

3x² + 7x = -2
-2, -1/3

2: x² - 49 = 0
-7, 7

3: x2 + 5x + 4 = 0
-1, -4

4: 6x2 - 2 = x
-1/2, 2/3

5: x2 - x = 42
7, -6

6: x² - 21x - 72 = 0
24, -3

7: 7x² - 7x - 2x + 2 = 0
2/7, 1

8: 3x² - 2x - 5 = 0
5/3, -1

9: 2a² - 9a = 5
-1/2, 5

10: 33x² - x - 14 = 0
2/3, -7/11

11: 21x² + 22x - 24 = 0
2/3, -12/7

12: 2x2 + 2x = 60
5, -6

13: x2 + 16x + 48 = 0
-4, -12

14: x3 - x2 - 12x = 0
-3, 4, 0

15: 4x² + 8x + 4 = 0
-1


I hope that helps!! :-)

Answer 2

You want us to do ALL your homework for you?
For 3x² + 7x = - 2 move the 2 to the LHS for standard form,
3x² + 7x + 2 = 0
Now you need a combination of the factors of 3 and 2 that add to 7. The only possible combination is 3*2 + 1*1, so you have
(3x + 1)(x + 2) = 0

The rest are up to you.

Answer 3

1) 3x2+7x=-2
x(3x+7)=-2
x=-2 or 3x+7=-2
3x+7+2=0
x=-9/3=3

2) x2-49=0
x2=7 or -7

3) x2+5x+4=0
(x+1)(x=4)=0
x=-1 or4

4) 6x2-2=x
6x2-x-2=0
(3x-2)(2x+1)=0
x=2/3 or-1/2

5) x2-2=42
(x-7)(x+6)=0
x=7 or -6

6) x2-21x-72=0
(x-24)(x+3)=0
x=24 or-3

7)7x2-7x-2x+2=0
(7x-2)(x-1)=0
x=x/7 or1

8)3x2-2x-5=0
(3x-5)(x+1)=0
x=5/3 or -1

this is all i can help
happy doing the rest!

Answer 4

x^2 + 5x - 14 = 0 14 may be produced via multiply a million and 14 at the same time, and a pair of and 7 at the same time. you want to choose on the two numbers although which could supply you 5 via the two including them of subtracting them from one yet another. for that reason, it incredibly is two and 7. for this reason: (x-2)(x+7) = x^2 + 7x - 2x - 14 = x^2 + 5x -14. Now (x-2)(x+7) will equivalent 0 whilst the two (x-2) = 0 and/or (x+7) = 0. (x-2) = 0 --> x = 2 (x+7) = 0 --> x = -7 for this reason, you solutions are: x = -7, 2 desire this helps :)